Question bank / Area and volume

Math · Geometry and TrigonometryHard

A cylindrical glass with an inside radius of 44 centimeters is partially filled with water. A solid metal ball with a radius of 33 centimeters is placed in the glass and sinks until it is completely under water. No water spills out. By how many centimeters does the water level rise?

A

2716\frac{27}{16}

B

94\frac{9}{4}

C

92\frac{9}{2}

D

99

Show answer and explanation

Answer: B

The water rises by a volume equal to the volume of the ball, 43π(3)3=36π\frac{4}{3}\pi(3)^3 = 36\pi cubic centimeters. This volume fills a cylinder of radius 44 and height hh, so π(4)2h=36π\pi(4)^2 h = 36\pi. Then 16h=3616h = 36, and h=94h = \frac{9}{4} centimeters.

Choice A leaves the 43\frac{4}{3} out of the volume of the ball, using π(3)3=27π\pi(3)^3 = 27\pi instead of 36π36\pi.

Why the other choices are wrong

  • A. This uses π times 3 cubed for the ball and leaves out the 4/3.
  • C. This divides by the circumference of the glass, 8π, instead of the area of its base, 16π.
  • D. This divides by 4π instead of 16π, so the radius of the glass wasn't squared.
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