Question bank / Circles

Math · Geometry and TrigonometryHard

Points AA and BB lie on a circle with center OO and radius 1010. The length of chord AB‾\overline{AB} is 10310\sqrt{3}. What is the length of the minor arc ABAB?

A

10π3\frac{10\pi}{3}

B

5π5\pi

C

40π3\frac{40\pi}{3}

D

20π3\frac{20\pi}{3}

Show answer and explanation

Answer: D

Draw the perpendicular from OO to the chord; it bisects AB‾\overline{AB} into halves of length 535\sqrt{3}. In the resulting right triangle with hypotenuse 1010, sin⁡(∠AOM)=5310=32\sin(\angle AOM) = \frac{5\sqrt{3}}{10} = \frac{\sqrt{3}}{2}, so ∠AOM=60∘\angle AOM = 60^\circ and ∠AOB=120∘\angle AOB = 120^\circ. The minor arc length is 120360⋅2π(10)=20π3\frac{120}{360} \cdot 2\pi(10) = \frac{20\pi}{3}.

Choice A results from taking the central angle to be 60∘60^\circ, which is only half of angle AOBAOB.

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