For x 12, the expression 6x + 52x - 1 is equivalent to 3 + A2x - 1, where A is a constant. What is the value of A?

SAT Equivalent expressions Practice Question 16 (Hard)

Math · Advanced MathHard

For $x \ne \frac{1}{2}$ , the expression $\frac{6x + 5}{2x - 1}$ is equivalent to $3 + \frac{A}{2x - 1}$ , where $A$ is a constant. What is the value of $A$ ?

$2$

$5$

$8$

$11$

Show answer and explanation

Answer: C

Write the numerator in terms of the denominator: $6x + 5 = 3(2x - 1) + 8$ . So $\frac{6x + 5}{2x - 1} = \frac{3(2x - 1)}{2x - 1} + \frac{8}{2x - 1} = 3 + \frac{8}{2x - 1}$ , and $A = 8$ .

Choice A subtracts 3 from 5, forgetting that $3(2x - 1)$ has a constant term of $-3$ .

Ask Owl about this question Next question

Got it wrong? On SAT Owl, Owl looks at the answer you chose and explains the exact mistake, then gives you similar questions until it sticks. Get your predicted SAT score free.