Question bank / Equivalent expressions

Math · Advanced MathEasy

The expression (4x−1)2(4x - 1)^2 is equivalent to ax2+bx+cax^2 + bx + c, where aa, bb, and cc are constants. What is the value of bb?

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Answer: -8

Expand: (4x−1)2=(4x−1)(4x−1)=16x2−4x−4x+1=16x2−8x+1(4x - 1)^2 = (4x - 1)(4x - 1) = 16x^2 - 4x - 4x + 1 = 16x^2 - 8x + 1. So b=−8b = -8.

Squaring each term separately gives 16x2+116x^2 + 1 and b=0b = 0, which leaves out the middle term.

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