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Math · Advanced MathMedium

The expression 3x2+7x−63x^2 + 7x - 6 can be written as (3x+a)(x+b)(3x + a)(x + b), where aa and bb are integers. What is the value of b−ab - a?

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Answer: 5

Expanding (3x+a)(x+b)(3x + a)(x + b) gives 3x2+(3b+a)x+ab3x^2 + (3b + a)x + ab. So ab=−6ab = -6 and 3b+a=73b + a = 7. Testing factor pairs of −6-6, the values a=−2a = -2 and b=3b = 3 work, since 3(3)+(−2)=73(3) + (-2) = 7. So 3x2+7x−6=(3x−2)(x+3)3x^2 + 7x - 6 = (3x - 2)(x + 3), and b−a=3−(−2)=5b - a = 3 - (-2) = 5.

Placing the numbers the other way, a=3a = 3 and b=−2b = -2, gives a middle coefficient of 3(−2)+3=−33(-2) + 3 = -3, not 77.

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