Question bank / Linear equations in one variable

Math · AlgebraHard

What value of xx satisfies the equation 23(6x−9)+12(4x+10)=3x+15\frac{2}{3}(6x - 9) + \frac{1}{2}(4x + 10) = 3x + 15?

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Answer: 16/3

Distribute: 4x−6+2x+5=3x+154x - 6 + 2x + 5 = 3x + 15. Combine like terms: 6x−1=3x+156x - 1 = 3x + 15. Subtract 3x3x and add 1: 3x=163x = 16, so x=163x = \frac{16}{3}.

Writing 23(−9)\frac{2}{3}(-9) as −3-3 instead of −6-6 leads to the incorrect value 133\frac{13}{3}.

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