Question bank / Linear functions

Math · AlgebraHard

For the linear function pp, p(1)=−3p(1) = -3 and p(5)=9p(5) = 9. If p(c)=30p(c) = 30, what is the value of cc?

A

88

B

1111

C

1212

D

8484

Show answer and explanation

Answer: C

The slope is 9−(−3)5−1=3\frac{9 - (-3)}{5 - 1} = 3, so p(x)=3x+bp(x) = 3x + b and −3=3+b-3 = 3 + b gives b=−6b = -6. Solve 3c−6=303c - 6 = 30: 3c=363c = 36, so c=12c = 12.

Choice D is p(30)p(30), the output when the input is 30, not the input that gives an output of 30.

Ask Owl about this questionNext question

Got it wrong? On SAT Owl, Owl looks at the answer you chose and explains the exact mistake, then gives you similar questions until it sticks. Get your predicted SAT score free.