Question bank / Linear functions

Math · AlgebraEasy

For the linear function hh, h(0)=9h(0) = 9, and the value of h(x)h(x) decreases by 44 each time xx increases by 11. What is the value of h(6)h(6)?

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Answer: -15

The slope is −4-4 and the yy-intercept is 99, so h(x)=−4x+9h(x) = -4x + 9. Then h(6)=−4(6)+9=−24+9=−15h(6) = -4(6) + 9 = -24 + 9 = -15.

Using a slope of 44 instead of −4-4 gives h(6)=33h(6) = 33. The values decrease, so the slope is negative.

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