Question bank / Linear functions

Math · AlgebraHard

The function C(x)=0.06x+18C(x) = 0.06x + 18 gives a household's monthly electricity cost, in dollars, for using xx kilowatt-hours of electricity. Which function MM gives the monthly cost, in dollars, for using yy megawatt-hours of electricity? (11 megawatt-hour =1,000= 1{,}000 kilowatt-hours)

A

M(y)=0.00006y+18M(y) = 0.00006y + 18

B

M(y)=0.06y+0.018M(y) = 0.06y + 0.018

C

M(y)=60y+18M(y) = 60y + 18

D

M(y)=60y+18,000M(y) = 60y + 18{,}000

Show answer and explanation

Answer: C

Using yy megawatt-hours means using x=1,000yx = 1{,}000y kilowatt-hours. Substitute: M(y)=0.06(1,000y)+18=60y+18M(y) = 0.06(1{,}000y) + 18 = 60y + 18. The fixed charge of $18\$18 doesn't depend on usage, so it doesn't change.

Choice A divides 0.060.06 by 1,0001{,}000, but each megawatt-hour costs 1,0001{,}000 times as much as each kilowatt-hour, not less.

Why the other choices are wrong

  • A. This divides the rate by 1,000. A megawatt-hour is 1,000 kilowatt-hours, so it costs 1,000 times as much.
  • B. This keeps the per-unit rate and divides the fixed charge by 1,000. The rate should be multiplied by 1,000, and the fixed charge stays $18.
  • D. This multiplies the fixed $18 charge by 1,000, but that charge doesn't depend on how much electricity is used.
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