Question bank / Lines, angles, and triangles

Math · Geometry and TrigonometryHard

In triangle ABCABC, the measure of angle BB is 70∘70^\circ and the measure of angle CC is 40∘40^\circ. The bisector of angle AA intersects BC‾\overline{BC} at point DD. What is the measure of angle ADCADC?

A

105∘105^\circ

B

35∘35^\circ

C

75∘75^\circ

D

110∘110^\circ

Show answer and explanation

Answer: A

Angle AA measures 180∘−70∘−40∘=70∘180^\circ - 70^\circ - 40^\circ = 70^\circ, so the bisector creates two 35∘35^\circ angles. In triangle ADCADC, angle DAC=35∘DAC = 35^\circ and angle C=40∘C = 40^\circ. So angle ADC=180∘−35∘−40∘=105∘ADC = 180^\circ - 35^\circ - 40^\circ = 105^\circ.

Choice C is angle ADBADB (180∘−35∘−70∘180^\circ - 35^\circ - 70^\circ), the angle on the other side of the bisector.

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