Question bank / Nonlinear equations in one variable and systems of equations in two variables

Math · Advanced MathMedium

What is the solution to the equation 2x+3=x\sqrt{2x + 3} = x?

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Answer: 3

Square both sides: 2x+3=x22x + 3 = x^2, so x2−2x−3=0x^2 - 2x - 3 = 0 and (x−3)(x+1)=0(x - 3)(x + 1) = 0. The candidates are x=3x = 3 and x=−1x = -1. Check: 9=3\sqrt{9} = 3 works, but 1=1≠−1\sqrt{1} = 1 \ne -1, so −1-1 is extraneous. The only solution is 3.

Keeping −1-1 is the common error; squaring can create solutions that don't satisfy the original equation.

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