Question bank / Nonlinear equations in one variable and systems of equations in two variables

Math · Advanced MathHard

What value of xx satisfies the equation xx−2−4x+3=10(x−2)(x+3)\frac{x}{x - 2} - \frac{4}{x + 3} = \frac{10}{(x - 2)(x + 3)}?

Student-produced response: enter your answer.

Show answer and explanation

Answer: -1

Multiply every term by (x−2)(x+3)(x - 2)(x + 3): x(x+3)−4(x−2)=10x(x + 3) - 4(x - 2) = 10. Expand: x2+3x−4x+8=10x^2 + 3x - 4x + 8 = 10, so x2−x−2=0x^2 - x - 2 = 0 and (x−2)(x+1)=0(x - 2)(x + 1) = 0. The value x=2x = 2 makes a denominator 00, so it isn't a solution. The only solution is x=−1x = -1.

The value x=2x = 2 satisfies the equation after the fractions are cleared, but it makes x−2=0x - 2 = 0 in the original denominators, so it is extraneous.

Ask Owl about this questionNext question

Got it wrong? On SAT Owl, Owl looks at the answer you chose and explains the exact mistake, then gives you similar questions until it sticks. Get your predicted SAT score free, or take a free full-length practice test.