Question bank / Nonlinear functions

Math · Advanced MathMedium

What is the vertex of the graph of y=2(x+3)2−8y = 2(x + 3)^2 - 8 in the xyxy-plane?

A

(3,−8)(3, -8)

B

(−3,−8)(-3, -8)

C

(−3,8)(-3, 8)

D

(−6,−8)(-6, -8)

Show answer and explanation

Answer: B

An equation in the form y=a(x−h)2+ky = a(x - h)^2 + k has vertex (h,k)(h, k). Writing x+3x + 3 as x−(−3)x - (-3) shows h=−3h = -3, and k=−8k = -8. So the vertex is (−3,−8)(-3, -8).

Choice A uses the sign shown inside the parentheses instead of its opposite.

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