Question bank / Nonlinear functions

Math · Advanced MathMedium

The height, in feet, of a ball tt seconds after it is thrown is modeled by h(t)=−16t2+64t+5h(t) = -16t^2 + 64t + 5. What is the maximum height, in feet, the ball reaches?

A

55

B

6464

C

6969

D

133133

Show answer and explanation

Answer: C

The maximum occurs at the vertex, where t=−642(−16)=2t = -\frac{64}{2(-16)} = 2. Then h(2)=−16(4)+64(2)+5=−64+128+5=69h(2) = -16(4) + 64(2) + 5 = -64 + 128 + 5 = 69 feet.

Choice A is the starting height, h(0)h(0), not the maximum height.

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