Question bank / One-variable data: distributions and measures of center and spread

Math · Problem-Solving and Data AnalysisHard

A data set has a mean of 1212 and a standard deviation of 44. Each value in the data set is multiplied by 33, and then 55 is subtracted from each result. What are the mean and standard deviation of the new data set?

A

Mean 3131, standard deviation 77

B

Mean 3636, standard deviation 1212

C

Mean 3131, standard deviation 44

D

Mean 3131, standard deviation 1212

Show answer and explanation

Answer: D

Applying the same operations to every value applies them to the mean: 3(12)−5=313(12) - 5 = 31. Multiplying every value by 33 triples the distances between values, so the standard deviation becomes 3(4)=123(4) = 12. Subtracting 55 from every value shifts the data without changing its spread, so the standard deviation stays 1212.

Choice A applies the subtraction to the standard deviation, but shifting every value by the same amount does not change spread.

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