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Math · Problem-Solving and Data AnalysisHard

A quantity is increased by p%p\%, and the result is then decreased by p%p\%, where p>0p > 0. The final value is 96%96\% of the original value. What is the value of pp?

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Answer: 20

An increase of p%p\% multiplies the quantity by 1+p1001 + \frac{p}{100}, and a decrease of p%p\% multiplies it by 1−p1001 - \frac{p}{100}. So (1+p100)(1−p100)=0.96\left(1 + \frac{p}{100}\right)\left(1 - \frac{p}{100}\right) = 0.96, which simplifies to 1−p210,000=0.961 - \frac{p^2}{10{,}000} = 0.96. Then p2=400p^2 = 400, and since p>0p > 0, p=20p = 20.

It's tempting to answer 44 because the value drops by 4%4\%, but a 4%4\% increase followed by a 4%4\% decrease leaves 99.84%99.84\% of the original value.

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