Question bank / Right triangles and trigonometry

Math · Geometry and TrigonometryHard

In triangle ABCABC, angle BB is a right angle, AC=20AC = 20, and tan⁡A=34\tan A = \frac{3}{4}. Point DD lies on AC‾\overline{AC} so that BD‾\overline{BD} is perpendicular to AC‾\overline{AC}. What is the length of BD‾\overline{BD}?

A

7.27.2

B

1212

C

12.812.8

D

9.69.6

Show answer and explanation

Answer: D

Since tan⁡A=BCAB=34\tan A = \frac{BC}{AB} = \frac{3}{4}, the sides are in the ratio 3:4:53:4:5, so with hypotenuse AC=20AC = 20, BC=12BC = 12 and AB=16AB = 16. The area of the triangle is 12(16)(12)=96\frac{1}{2}(16)(12) = 96. Using AC‾\overline{AC} as the base, 12(20)(BD)=96\frac{1}{2}(20)(BD) = 96, so BD=9.6BD = 9.6.

Choice A is the length of CD‾\overline{CD} (since CD=BCcos⁡C=12⋅35CD = BC \cos C = 12 \cdot \frac{3}{5}), not the altitude.

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