Question bank / Right triangles and trigonometry

Math · Geometry and TrigonometryHard

In triangle ABCABC, the measure of angle AA is 45∘45^\circ and the measure of angle BB is 30∘30^\circ. The altitude from CC to AB‾\overline{AB} has length 66. What is the length of AB‾\overline{AB}?

A

6+636 + 6\sqrt{3}

B

1212

C

12+6212 + 6\sqrt{2}

D

6+236 + 2\sqrt{3}

Show answer and explanation

Answer: A

Let DD be the foot of the altitude on AB‾\overline{AB}. Triangle ADCADC is a 45∘45^\circ-45∘45^\circ-90∘90^\circ triangle, so AD=CD=6AD = CD = 6. Triangle BDCBDC is a 30∘30^\circ-60∘60^\circ-90∘90^\circ triangle with CD=6CD = 6 opposite the 30∘30^\circ angle, so BD=63BD = 6\sqrt{3}. Thus AB=6+63AB = 6 + 6\sqrt{3}.

Choice D uses BD=63=23BD = \frac{6}{\sqrt{3}} = 2\sqrt{3}, which swaps the roles of the legs in the 30∘30^\circ-60∘60^\circ-90∘90^\circ triangle.

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