SAT Right triangles and trigonometry Practice Question 11 (Easy)

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Question bank / Right triangles and trigonometry

Math · Geometry and TrigonometryEasy

A right triangle has legs of length $5$ and $12$ . What is the sine of the angle opposite the side of length $5$ ?

$\frac{5}{12}$

$\frac{5}{13}$

$\frac{12}{13}$

$\frac{13}{5}$

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Answer: B

The hypotenuse is $\sqrt{5^2 + 12^2} = \sqrt{169} = 13$ . Sine is the opposite side over the hypotenuse, so the sine of the angle opposite the side of length $5$ is $\frac{5}{13}$ .

Choice A is the tangent of the angle (opposite over adjacent), not the sine.

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