Question bank / Right triangles and trigonometry

Math · Geometry and TrigonometryHard

In triangle PQRPQR, PQ=PR=10PQ = PR = 10 and QR=12QR = 12. What is the value of cos⁡Q\cos Q?

A

45\frac{4}{5}

B

34\frac{3}{4}

C

43\frac{4}{3}

D

35\frac{3}{5}

Show answer and explanation

Answer: D

Draw the altitude from PP to QR‾\overline{QR}, meeting it at MM. Because the triangle is isosceles, MM is the midpoint of QR‾\overline{QR}, so QM=6QM = 6. In right triangle PMQPMQ, cos⁡Q=QMPQ=610=35\cos Q = \frac{QM}{PQ} = \frac{6}{10} = \frac{3}{5}.

Choice A is sin⁡Q=PMPQ=810\sin Q = \frac{PM}{PQ} = \frac{8}{10}, which uses the altitude instead of the adjacent side.

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