Question bank / Systems of two linear equations in two variables

Math · AlgebraMedium

A coffee shop sells small coffees for $3.50\$3.50 each and large coffees for $4.25\$4.25 each. One morning it sold 120120 coffees for a total of $462\$462. How many large coffees did it sell that morning?

A

4242

B

5656

C

6464

D

132132

Show answer and explanation

Answer: B

Let SS be the number of small coffees and LL the number of large coffees. Then S+L=120S + L = 120 and 3.50S+4.25L=4623.50S + 4.25L = 462. Substituting S=120−LS = 120 - L gives 420−3.50L+4.25L=462420 - 3.50L + 4.25L = 462, so 0.75L=420.75L = 42 and L=56L = 56.

Choice C, 6464, is the number of small coffees.

Why the other choices are wrong

  • A. 42 dollars is the revenue above 120 × $3.50. Divide it by the $0.75 price difference to get the number of large coffees.
  • C. 64 is the number of small coffees, not large coffees.
  • D. This divides $462 by $3.50, as if every coffee sold were small.
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