Question bank / Systems of two linear equations in two variables

Math · AlgebraMedium

Sofia has $1,200\$1{,}200 in savings and adds $35\$35 each week. Mateo has $2,000\$2{,}000 in savings and adds $15\$15 each week. The equations y=1,200+35xy = 1{,}200 + 35x and y=2,000+15xy = 2{,}000 + 15x model their savings, yy dollars, after xx weeks. The solution to this system is (40,2,600)(40, 2{,}600). What is the best interpretation of this solution?

A

After 4040 weeks, Sofia and Mateo will each have $2,600\$2{,}600 in savings.

B

After 4040 weeks, Sofia and Mateo will have a combined total of $2,600\$2{,}600 in savings.

C

After 2,6002{,}600 weeks, Sofia and Mateo will each have $40\$40 in savings.

D

After 2,6002{,}600 weeks, Sofia will have $40\$40 more in savings than Mateo.

Show answer and explanation

Answer: A

In the solution (40,2,600)(40, 2{,}600), x=40x = 40 weeks and y=2,600y = 2{,}600 dollars, and the point lies on both lines. So after 4040 weeks each person has $2,600\$2{,}600: 1,200+35(40)=2,6001{,}200 + 35(40) = 2{,}600 and 2,000+15(40)=2,6002{,}000 + 15(40) = 2{,}600.

Choice B adds their savings, but each equation gives one person's savings, and the solution is where those two amounts are equal.

Why the other choices are wrong

  • B. Each equation models one person's savings. At the solution each person has $2,600, so together they have $5,200.
  • C. This switches the variables. x is the number of weeks, 40, and y is the amount saved, $2,600.
  • D. This switches the variables, and the solution is where the two amounts are equal, not where they differ.
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