Question bank / Two-variable data: models and scatterplots

Math · Problem-Solving and Data AnalysisMedium

A veterinarian recorded the weight xx, in pounds, and the amount of food yy, in cups, eaten per day by 2525 dogs. The line of best fit for the data is y=0.05x+0.8y = 0.05x + 0.8. Based on the line of best fit, if one dog weighs 2020 pounds more than another dog, how many more cups of food per day is the heavier dog predicted to eat?

A

0.050.05

B

0.80.8

C

11

D

1.81.8

Show answer and explanation

Answer: C

The slope, 0.050.05, is the predicted increase in daily food, in cups, for each additional pound. For 2020 additional pounds, the predicted increase is 20×0.05=120 \times 0.05 = 1 cup.

Choice D is the predicted amount of food for a dog that weighs 2020 pounds, which includes the 0.80.8, but the question asks for the difference between two dogs.

Why the other choices are wrong

  • A. 0.05 is the predicted increase for each 1 pound, not for 20 pounds.
  • B. 0.8 is the y-intercept, the predicted amount for a dog that weighs 0 pounds.
  • D. 1.8 is the predicted amount for a dog that weighs 20 pounds, not the difference between two dogs.
Ask Owl about this questionNext question

Got it wrong? On SAT Owl, Owl looks at the answer you chose and explains the exact mistake, then gives you similar questions until it sticks. Get your predicted SAT score free, or take a free full-length practice test.