Question bank / Circles

Math · Geometry and TrigonometryEasy

A circle in the xyxy-plane has equation (x−3)2+(y+2)2=16(x - 3)^2 + (y + 2)^2 = 16. What are the center and radius of the circle?

A

Center (−3,2)(-3, 2), radius 44

B

Center (3,−2)(3, -2), radius 1616

C

Center (3,−2)(3, -2), radius 44

D

Center (−3,2)(-3, 2), radius 1616

Show answer and explanation

Answer: C

The standard form is (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2, with center (h,k)(h, k) and radius rr. Here h=3h = 3, k=−2k = -2, and r2=16r^2 = 16, so the center is (3,−2)(3, -2) and the radius is 44.

Choice B uses 1616 as the radius, but 1616 is r2r^2.

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