Question bank / Equivalent expressions

Math · Advanced MathMedium

The expression (3x+2)(2x−5)(3x + 2)(2x - 5) is equivalent to ax2+bx+cax^2 + bx + c, where aa, bb, and cc are constants. What is the value of a+b+ca + b + c?

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Answer: -15

Expand: 6x2−15x+4x−10=6x2−11x−106x^2 - 15x + 4x - 10 = 6x^2 - 11x - 10. So a+b+c=6−11−10=−15a + b + c = 6 - 11 - 10 = -15. (Shortcut: a+b+ca + b + c is the value of the expression at x=1x = 1, which is (5)(−3)=−15(5)(-3) = -15.)

Writing the middle term as +11x+11x instead of −11x-11x gives the incorrect value 7.

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