Answer: B

With $20$ values, the median is the average of the $10$th and $11$th values. The cumulative counts are $3$ (for $0$), $8$ (through $1$), and $14$ (through $2$), so the $10$th and $11$th values are both $2$ and the median is $2$. The mean is $\frac{0(3)+1(5)+2(6)+3(4)+4(2)}{20} = \frac{37}{20} = 1.85$. Since $1.85 < 2$, the mean is less than the median.

Choice D is tempting because the individual values aren't listed, but a frequency table gives enough information to find both measures exactly.